document.write cannot change a document that has already been loaded in the browser. You could instead use DOM scripting to update the content of a page.

In the example above, after the </form> insert the following line:
<div id="output"></div>

Now you can append content to this by using DOM manipulation, so instead of
tmpStr += this.city + " " + this.state +
" " + this.zip + "n" + "<br>";
do this instead:

var d = document
var el = d.getElementById("output");
el.appendChild(
d.createTextNode(
this.city + " " +
this.state + " " +
this.zip + "n")
);
el.appendChild(
d.createElement("br")
);

Javascript form validation is by no means trivial, and depends almost entirely on your definition of "valid" for each field. Most methods, however, follow a similar structure:

1. Retrieve the element(s) to be validated.
2. Pass the value of the element to a function that will return true/false if the value is "valid".
3. Repeat as desired until a decision is made whether the form itself is "valid".

W3Schools has a decent conceptual overview.

its the ram and the CPU that make the computer go faster. try getting some high performance RAM

hope this helps!!

You need to add target="popUpWindow" in your form header.

Since your js says window.open(url,'popUpWindow' ,,,,

your target has to be "popUpWindow" not "popup"

I use this code on my garden site for glossary terms.